No.
01 - Binary Search Tree and Double-linked List

Convert a binary search tree to a sorted double-linked list. We can only change the target of pointers, but cannot create any new nodes.

No. 04 - Paths with Specified Sum in Binary Tree

All nodes along children pointers from root to leaf nodes form a path in a binary tree. Given a binary tree and a number, please print out all of paths where the sum of all nodes value is same as the given number.

No. 06 - Post-order Traversal Sequences of Binary Search Trees

Determine whether an input array is a post-order traversal sequence of a binary tree or not. If it is, return true; otherwise return false. Assume all numbers in an input array are unique.

No. 31 - Binary Search Tree Verification

How to verify whether a binary tree is a binary search tree?

No. 45 - Closest Node in a Binary Search Tree

Given a binary search tree and a value

Convert a binary search tree to a sorted double-linked list. We can only change the target of pointers, but cannot create any new nodes.

No. 04 - Paths with Specified Sum in Binary Tree

All nodes along children pointers from root to leaf nodes form a path in a binary tree. Given a binary tree and a number, please print out all of paths where the sum of all nodes value is same as the given number.

No. 06 - Post-order Traversal Sequences of Binary Search Trees

Determine whether an input array is a post-order traversal sequence of a binary tree or not. If it is, return true; otherwise return false. Assume all numbers in an input array are unique.

No. 31 - Binary Search Tree Verification

How to verify whether a binary tree is a binary search tree?

No. 45 - Closest Node in a Binary Search Tree

Given a binary search tree and a value

*k*, please find a node in the binary search tree whose value is closest to*k*.
Given a binary search tree, please check whether there are two nodes in it whose sum equals a given value.

helpful..Thanks:)

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which traversal is same in a binary tree and its mirror image

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public BSTNode toDoublyLinkedlIst() {

ReplyDeleteBSTNodetest = inorder2(root);

while (test != null ) {

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public BSTNode inorder2(BSTNode node) {

if (node.left == null && node.right == null) {

return node;

}

BSTNode nodeLeft = inorder2(node.left);

nodeLeft.right = node;

BSTNode nodeRight = inorder2(node.right);

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public BSTNode toDoublyLinkedlIst() {

ReplyDeleteBSTNodetest = inorder2(root);

while (test != null ) {

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public BSTNode inorder2(BSTNode node) {

if (node.left == null && node.right == null) {

return node;

}

BSTNode nodeLeft = inorder2(node.left);

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}

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